Solution - Triangles on the Same Base and Between the Same Parallels



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ConceptTriangles on the Same Base and Between the Same Parallels  


In the given figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that:

(i) ar (DOC) = ar (AOB)

(ii) ar (DCB) = ar (ACB)

(iii) DA || CB or ABCD is a parallelogram.

[Hint: From D and B, draw perpendiculars to AC.]


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Solution for concept: Triangles on the Same Base and Between the Same Parallels. For the course 8th-10th CBSE