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Solution - Triangles on the Same Base and Between the Same Parallels

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ConceptTriangles on the Same Base and Between the Same Parallels  

Question

In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that

(i) ar (ACB) = ar (ACF)

(ii) ar (AEDF) = ar (ABCDE)

Solution

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Reference Material

Solution for concept: Triangles on the Same Base and Between the Same Parallels. For the course CBSE
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