ConceptTriangles on the Same Base and Between the Same Parallels

#### My Profile

My Profile [view full profile]

why create a profile on shaalaa.com?

1. Inform you about time table of exam.

2. Inform you about new question papers.

3. New video tutorials information.

1. Inform you about time table of exam.

2. Inform you about new question papers.

3. New video tutorials information.

#### Question

In the following figure, D and E are two points on BC such that BD = DE = EC. Show that ar (ABD) = ar (ADE) = ar (AEC).

Can you answer the question that you have left in the ’Introduction’ of this chapter, whether the field of *Budhia* has been actually divided into three parts of equal area?

[**Remark:** Note that by taking BD = DE = EC, the triangle ABC is divided into three triangles ABD, ADE and AEC of equal areas. In the same way, by dividing BC into *n* equal parts and joining the points of division so obtained to the opposite vertex of BC, you can divide ΔABC into *n* triangles of equal areas.]

clickto share

#### Solution

You need to to view the solution

Is there an error in this question or solution?

#### Similar questions VIEW ALL

#### Reference Material

Solution for concept: Triangles on the Same Base and Between the Same Parallels. For the course CBSE