#### Question

In the given figure, AP || BQ || CR. Prove that ar (AQC) = ar (PBR).

#### Solution

Since ΔABQ and ΔPBQ lie on the same base BQ and are between the same parallels AP and BQ,

∴ Area (ΔABQ) = Area (ΔPBQ) ... (1)

Again, ΔBCQ and ΔBRQ lie on the same base BQ and are between the same parallels BQ and CR.

∴ Area (ΔBCQ) = Area (ΔBRQ) ... (2)

On adding equations (1) and (2), we obtain

Area (ΔABQ) + Area (ΔBCQ) = Area (ΔPBQ) + Area (ΔBRQ)

⇒ Area (ΔAQC) = Area (ΔPBR)

Is there an error in this question or solution?

Solution In the given figure, AP || BQ || CR. Prove that ar (AQC) = ar (PBR). Concept: Triangles on the Same Base and Between the Same Parallels.