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Question - Triangles on the Same Base and Between the Same Parallels

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ConceptTriangles on the Same Base and Between the Same Parallels  

Question

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar (APB) × ar (CPD) = ar (APD) × ar (BPC).

[Hint : From A and C, draw perpendiculars to BD.]

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