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Explain the Process of Translation - HSC Science (General) 12th Board Exam - Biology

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Question

Explain the process of translation

Solution

Translation:
Translation is the process in which the sequence of codons on the mRNA strand is used (read/decoded) and accordingly the amino acids are joined to each other to form a polypeptide chain that makes protein.
The process involves the following steps:

a. Activation of amino acids and formation of AA-tRNA complex:
In presence of an enzyme aminoacyl tRNA synthetase, the amino acid (AA) molecule is activated and each amino acid is attached to the specific tRNA molecule at 3'/CCA end to form aminoacyl-tRNA complex. The reaction requires ATP. This process is called charging
of tRNA or aminoacylation of tRNA.
b. Formation of the polypeptide chain: It is the actual translation which involves the following steps:
Initiation:
It begins with the formation of initiation complex which requires the mRNA having codons for a polypeptide, the smaller (30S) and larger (50S) subunits of the ribosome, the initial AA1 tRNA complex and ATP and GTP as a source of energy. The process of initiation needs initiation factors.
In prokaryotes, the first AA1-tRNA complex has amino acid, N-formyl-methionine (f-met); In eukaryotes, it is methionine (met). The process starts with binding of mRNA on the smaller 30S subunit of the ribosome. The start codon AUG is positioned properly. The AA1-tRNA complex, i.e. f-met-tRNA complex now gets attached to the start codon
AUG. This is done with the help of anticodon UAC of tRNA. Small and large subunits of ribosome join to form 70S ribosome. The ribosome has three sites namely, Aminoacyl site (A), Peptidyl site (P) and Exit site (E). The empty tRNA leaves from E site. Only the AA1-tRNA complex binds at P site directly, while all the other incoming tRNA
complexes get attached first at A site and then are shifted to P site. The polypeptide chain is released from P-site. In eukaryotes, 40S (smaller subunit) and 60S (larger subunit) combine to form 80S type of ribosome.

Elongation:
This is done by the formation of peptide linkages/bonds in between the successive amino acid molecules (AA1, AA2, AA3 and so on). The elongation activity is catalyzed by the enzyme peptidyl transferase. Each tRNA complex brings a specific amino acid. Due to complementary nature of anticodons and codons, the amino acids are placed to their proper positions. During elongation, the ribosome moves along the mRNA in a stepwise manner from start to stop codon (5'→ 3'), one codon ahead each time. This movement is called translocation. In every step of translocation, one amino acid is added in the polypeptide chain causing elongation.
Termination:
When the mRNA reaches the last termination codon, i.e. either UAA, UAG or UGA, termination occurs.In identifying the stop/termination codon and in releasing the polypeptide chain from the site, the release or termination factors R1, R2, and S play an important role. After termination, the smaller (30S) and larger (50S) subunits of ribosome get separated from each other. In order to increase the cellular efficiency of protein synthesis, many ribosomes may bind to the mRNA strand and form the polypeptide chain for the synthesis of the protein molecule. Such a
structure with many ribosomes bound to mRNA is called polysomes or polyribosome.

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APPEARS IN

 2015-2016 (July) (with solutions)
Question 4.1 | 7.00 marks

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Solution Explain the Process of Translation Concept: Transcription - Introduction of Transcription.
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