Maharashtra State BoardSSC (English Medium) 9th Standard
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Total Surface Area of a Cube is 5400 Sq. Cm. Find the Surface Area of All Vertical Faces of the Cube. - Geometry

Sum

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

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Solution

Let the edge of the cube be l cm.
Total surface area of the cube = 5400 cm2

∴ 6l2 = 5400
⇒ l2 = `5400/6` = 900

⇒ l = `sqrt900` = 30 cm

∴ Surface area of all vertical faces of the cube
= 4l2 
= 4 × (30 cm)2 
= 4 × 900 cm2 
= 3600 cm2
Thus, the surface area of all vertical faces of the cube is 3600 cm2.

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APPEARS IN

Balbharati Mathematics 2 Geometry 9th Standard Maharashtra State Board
Chapter 9 Surface Area and Volume
Practice Set 9.1 | Q 4 | Page 115
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