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Sum

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

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#### Solution

Let the edge of the cube be l cm.

Total surface area of the cube = 5400 cm^{2}

∴ 6l^{2} = 5400

⇒ l^{2} = `5400/6` = 900

⇒ l = `sqrt900` = 30 cm

∴ Surface area of all vertical faces of the cube

= 4l^{2}

= 4 × (30 cm)^{2}

= 4 × 900 cm^{2}

= 3600 cm^{2}

Thus, the surface area of all vertical faces of the cube is 3600 cm^{2}.

Concept: Surface Area of a Cuboid

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