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Toricelli’S Barometer Used Mercury. Pascal Duplicated It Using French Wine of Density 984 Kg M–3. Determine the Height of the Wine Column for Normal Atmospheric Pressure. - CBSE (Science) Class 11 - Physics

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Question

Toricelli’s barometer used mercury. Pascal duplicated it using French wine of density 984 kg m–3. Determine the height of the wine column for normal atmospheric pressure.

Solution 1

10.5 m

Density of mercury, ρ1 = 13.6 × 103 kg/m3

Height of the mercury column, h1 = 0.76 m

Density of French wine, ρ2 = 984 kg/m3

Height of the French wine column = h2

Acceleration due to gravity, g = 9.8 m/s2

The pressure in both the columns is equal, i.e.,

Pressure in the mercury column = Pressure in the French wine column

`rho_1h_1g = rho_2h_2g`

`h_2 = (rho_1h_1)/rho_2`

`= (13.6xx10^3xx0.76)/984`

= 10.5 m

Hence, the height of the French wine column for normal atmospheric pressure is 10.5 m

Solution 2

We know that atmospheric pressure, `P = 1.01 xx 10^5 "Pa"`

If we use French wine of density,  `rho= 984 kg m^(-3)`, then height of wine column should be

`h_(m')` such that `p = hrhog`

`=> h_m = P/(rhog) = (1.01xx10^5)/(984xx9.8) = 10.47m ~~10.5 m`

 

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APPEARS IN

 NCERT Solution for Physics Textbook for Class 11 (2018 to Current)
Chapter 10: Mechanical Properties of Fluids
Q: 6 | Page no. 269
Solution Toricelli’S Barometer Used Mercury. Pascal Duplicated It Using French Wine of Density 984 Kg M–3. Determine the Height of the Wine Column for Normal Atmospheric Pressure. Concept: Pressure - Concept of Pressure.
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