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To get from point A to point B you must avoid walking through a pond. You must walk 34 m south and 41 m east. To the nearest meter, how many meters would be saved if it were possible to make a way through the pond?

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#### Solution

In the right ∆ABC,

By Pythagoras theorem

AC^{2 }= AB^{2} + BC^{2}

= 34^{2} + 41^{2}

= 1156 + 1681

= 2837

AC = `sqrt(2837)`

= 53.26 m

A one must walk (34m + 41m) 75m to reach C.

The difference in Distance = 75 – 53.26

= 21.74 m

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