Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads

MCQ

Fill in the Blanks

To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is ______.

#### Options

8

10

11

12

Advertisement Remove all ads

#### Solution

To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is **12**.

**Explanation:-**

We know that to divide a line segment in the ratio m : n, first draw a ray AX which makes an acute angle BAX, then marked m+n points at equal distances from each other.

Here m = 5, n = 7

So minimum number of these point = m + n = 5 + 7 = 12

Concept: Division of a Line Segment

Is there an error in this question or solution?