# To construct a triangle similar to a given ΔABC with its sides 8/5 of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle - Mathematics

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To construct a triangle similar to a given ΔABC with its sides 8/5 of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. Then minimum number of points to be located at equal distances on ray BX is ______.

• 5

• 8

• 13

• 3

#### Solution

To construct a triangle similar to a given ΔABC with its sides 8/5 of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. Then minimum number of points to be located at equal distances on ray BX is 8.

Explanation:-

To construct a triangle similar to a given triangle with its sides m/n of the corresponding sides of given triangle, the minimum number of points to be located at equal distance is equal to the greater of m and n in m/n.

Here, m/n=8/5

So the minimum number of points to be located at equal distance on ray BX is 8.

Concept: Division of a Line Segment
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#### APPEARS IN

NCERT Mathematics Exemplar Class 10
Chapter 10 Construction
Exercise 10.1 | Q 5 | Page 114
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