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Three resistors 1 Ω, 2 Ω, and 3 Ω are combined in series. What is the total resistance of the combination?

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#### Solution

Three resistors of resistances 1 Ω, 2 Ω, and 3 Ω are combined in series. The total resistance of the combination is given by the algebraic sum of individual resistances.

Total resistance = 1 + 2 + 3 = 6 Ω

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