#### Question

Three identical cars A, B and C are moving at the same speed on three bridges. The car A goes on a place bridge, B on a bridge convex upward and C goes on a bridge concave upward. Let F_{A}, F_{B} and F_{C} be the normal forces exerted by the car on the bridges when they are at the middle of bridges.

F

_{A}is maximum of the three forces.F

_{B}is maximum of the three forces.F

_{C}is maximum of the three forces.F

_{A}= F_{B}_{ }= F_{C}.

#### Solution

F_{C} is maximum of the three forces.

At the middle of bridge, normal force can be given as : \[\text{N}_\text{A} = \text{mg}\]

\[\text{N}_\text{B} = \frac{\text{mv}^2}{\text{r}} - \text{mg}\]

\[ \text{N}_\text{C} = \frac{\text{mv}^2}{\text{r}} + \text{mg}\]

So, F_{C} is maximum.

Is there an error in this question or solution?

Solution Three Identical Cars A, B and C Are Moving at the Same Speed on Three Bridges. the Car a Goes on a Place Bridge, B on a Bridge Convex Upward and C Goes on a Bridge Concave Upward. Concept: Circular Motion.