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Solution - If lines (x−1)/2=(y+1)/3=(z−1)/4 and  (x−3)/1=(y−k)/2=z/1 intersect, then find the value of k and hence find the equation of the plane containing these lines. - Three - Dimensional Geometry Examples and Solutions

ConceptThree - Dimensional Geometry Examples and Solutions

Question

If lines `(x−1)/2=(y+1)/3=(z−1)/4 and  (x−3)/1=(y−k)/2=z/1` intersect, then find the value of k and hence find the equation of the plane containing these lines.

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Reference Material

Solution for question: If lines (x−1)/2=(y+1)/3=(z−1)/4 and  (x−3)/1=(y−k)/2=z/1 intersect, then find the value of k and hence find the equation of the plane containing these lines. concept: Three - Dimensional Geometry Examples and Solutions. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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