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Solution - Find the distance between the point (−1, −5, −10) and the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane x-y+z=5 - Three - Dimensional Geometry Examples and Solutions

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Question

Find the distance between the point (−1, −5, −10) and the point of intersection of the line `(x-2)/3=(y+1)/4=(z-2)/12` and the plane x-y+z=5

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Reference Material

Solution for question: Find the distance between the point (−1, −5, −10) and the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane x-y+z=5 concept: Three - Dimensional Geometry Examples and Solutions. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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