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# Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes: - Mathematics

Answer in Brief

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:

 Outcome: No head One head Two heads Three heads Frequency: 14 38 36 12

If the three coins are simultaneously tossed again, compute the probability of:
(i) 2 heads coming up.
(ii) 3 heads coming up.
(iii) at least one head coming up.
(iv) getting more heads than tails.
(v) getting more tails than heads.

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#### Solution

The total number of trials is 100.

Remember the empirical or experimental or observed frequency approach to probability.

If n be the total number of trials of an experiment and A is an event associated to it such that A happens in m-trials. Then the empirical probability of happening of event is denoted by P (A ) and is given by

P (A) =m/n

(i) Let be the event of getting two heads.

The number of times A happens is 36.

Therefore, we have

P (A) =36 /100

=0.36

(ii) Let B be the event of getting three heads

The number of times B happens is 12.

Therefore, we have

P (B) =12/100

=0.12

(iii) Let C be the event of getting at least one head.

The number of times C happens is 38+36+12=86.

Therefore, we have

P (c) =86/100

=0.86

(iv) Let D be the event of getting more heads than tails.

The number of times D happens is 36+ 12+ 48 .

Therefore, we have

P (D) =48/100

=0.48

(v) Let be the event of getting more tails than heads.

The number of times E happens is 14+38+=52.

Therefore, we have

P (E) =52/100

=0.52 .

Is there an error in this question or solution?
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 25 Probability
Exercise 25.1 | Q 3 | Page 13
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