Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel.
(a) What is the total capacitance of the combination?
(b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
(a) Capacitances of the given capacitors are
For the parallel combination of the capacitors, equivalent capacitorC'is given by the algebraic sum,
Therefore, total capacitance of the combination is 9 pF.
(b) Supply voltage, V = 100 V
The voltage through all the three capacitors is same = V = 100 V
Charge on a capacitor of capacitance C and potential difference V is given by the relation,
q = VC … (i)
For C = 2 pF,
Charge = VC=100 x 2=200pC=`2xx10^-19C`
For C = 3 pF,
Charge = VC=100 x 3=300pC=`3xx10^-19C`
For C = 4 pF,
Charge = VC=100 x 4=400pC=`4xx10^-19C`
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