Answer in Brief

The volume of a cuboidal box is 48 cm^{3}. If its height and length are 3 cm and 4 cm respectively, find its breadth.

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#### Solution

\[\text { Suppose that the breadth of the box is b cm }. \]

\[\text { Volume of the cuboidal box = 48 } {cm}^3 \]

\[\text { Height of the box }= 3 cm \]

\[\text { Length of the box }= 4 cm\]

\[\text { Now, volume of box = length }\times \text { breadth } \times \text { height }\]

\[ \Rightarrow 48 = 4 \times b \times 3\]

\[ \Rightarrow 48 = 12 \times b\]

\[ \Rightarrow b = \frac{48}{12} = 4 cm\]

\[ \therefore \text { The breadth of the cuboidal box is 4 cm } .\]

Concept: Surface Area of a Cuboid

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