Maharashtra State BoardHSC Commerce 11th
Advertisement Remove all ads

The vertices of a triangle are A(3, 4), B(2, 0) and C(–1, 6). Find the equations of side BC - Mathematics and Statistics

Sum

The vertices of a triangle are A(3, 4), B(2, 0) and C(–1, 6). Find the equations of side BC

Advertisement Remove all ads

Solution

Vertices of ΔABC are A(3, 4), B(2, 0) and C(–1, 6).
Equation of a line in two point form is

`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`

∴ the equation of the side BC is

`(y - 0)/(6 - 0) = (x - 2)/(-1 - 2)        ...[("B" = (x_1,y_1) = (2, 0)),("C" = (x_2,y_2) = (-1, 6))]`

∴ `y/6 = (x - 2)/(-3)`

y = – 2 (x – 2)
∴ 2x + y – 4 = 0.

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) 11th Standard Maharashtra State Board
Chapter 5 Locus and Straight Line
Exercise 5.3 | Q 6. (a) | Page 73
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×