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The Two Square Faces of a Rectangular Dielectric Slab (Dielectric Constant 4⋅0) of Dimensions 20 Cm × 20 Cm × 1⋅0 Mm Are Metal-coated. Find the Capacitance Between the Coated Surfaces. - Physics

Sum

The two square faces of a rectangular dielectric slab (dielectric constant 4⋅0) of dimensions 20 cm × 20 cm × 1⋅0 mm are metal-coated. Find the capacitance between the coated surfaces.

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Solution

The area of the plates of the capacitor is given by 

`A = 20  "cm" xx 20  "cm" = 400  "cm"^2`

⇒ `A = 4 xx 10^-2  "m"`

The separation between the parallel plates is given by 

`d = 1  "m" = 1 xx 10^-3  "m"`

Here, the thickness of the dielectric is the same as the separation between the parallel plates.

Thus, the capacitance is given by

`C = (∈_0Ak)/d = ((8.85 xx 10^-12) xx (4 xx 10^-2) xx 4)/10^-3 = 1.42  "nF"`

Concept: Capacitors and Capacitance
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 9 Capacitors
Q 49 | Page 169
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