The Total Surface Area of a Hollow Cylinder Which is Open from Both Sides is 4620 Sq. Cm,Area of Base Ring is 115.5 Sq. Cm and Height 7 Cm. Find the Thickness of the Cylinder - Mathematics

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The total surface area of a hollow cylinder which is open from both sides is 4620 sq. cm,area of base ring is 115.5 sq. cm and height 7 cm. Find the thickness of the cylinder

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Let the inner radii of hollow cylinder rcm 
Outer radii of hollow cylinder Rcm 

`2πrh + 2πRh +2πR^2  - 2πr^2 = 4620 → (1)`

`πR^2 =πr^2 =115.5→(2)`

`⇒ 2πh(R+r)+2(πR^2-πr^2)=4620 and πR^2-m^2 = 115.5`

`⇒2πh(R+r)+231=4620 and π(R^2-r^2)=115.5`

`⇒2π× 7(r+R)=4389 and π(R^2-r^2)=115.5`

`⇒π (R+r)=313.5 and π (R+r) (R-r)=115.5`


`⇒ R-r=7/19cm`.

Concept: Surface Area of Cylinder
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RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.1 | Q 5 | Page 8

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