The time taken by a person to cover 150 km was 2 1/2 hours more than the time taken in the return journey. If he returned at a speed of 10 km/hour more than the speed while going, find the speed per hour in each direction.
Let the speed of the person while going be x km/h.
⇒ Speed of the person while returning = (x + 10) km/h
Time taken by the person while going = Time taken by the person while returning + 2`1/2` h
⇒x−20=0 or x+30=0
Since speed cannot be negative, x = 20.
⇒ Thus, speed of the person while going = 20 km/h
⇒ Speed of the person while returning = 20 + 10 = 30 km/h