The sum of a two digit number and the number obtained by reversing its digits is 121. Find the number if its units place digit is greater than the tens place digit by 7.
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Solution
Suppose, the units place digit of the two digit number is y and the tens place digit is x.
∴ the number is 10x + y
∴ the number obtained by reversing the digits is 10y + x
∴ from the given conditions,
`(10x+y)+(10y+x)=121`
∴ 11x+11y=121 ∴ x+y=11 .............(I)
Also, x=y+7 ∴ x-y=7 ................(II)
∴ Adding (I) and (II), `2x=18 x=9`
∴ from (I) `a+y=11` ` y=2`
∴ the two digit number is 29.
Concept: Simple Situational Problems
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