Advertisement Remove all ads

The Sum of a Two Digit Number and the Number Obtained by Reversing Its Digits is 121. Find the Number If Its Units Place Digit is Greater than the Tens Place Digit by 7. - Algebra

The sum of a two digit number and the number obtained by reversing its digits is 121. Find the number if its units place digit is greater than the tens place digit by 7. 

Advertisement Remove all ads


Suppose, the units place digit of the two digit number is y and the tens place digit is x.
∴ the number is 10x + y
∴ the number obtained by reversing the digits is 10y + x
∴ from the given conditions, 


∴ 11x+11y=121                                ∴ x+y=11 .............(I)

Also, x=y+7                                      ∴ x-y=7 ................(II) 

∴ Adding (I) and (II), `2x=18       x=9`

∴ from (I) `a+y=11`     `    y=2` 

∴ the two digit number is 29. 

Concept: Simple Situational Problems
  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads

View all notifications

      Forgot password?
View in app×