Advertisement Remove all ads

The Sum of Three Numbers in A.P. is 12 and Sum of Their Cubes is 288. Find the Numbers. - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

The sum of three numbers in A.P. is 12 and sum of their cubes is 288. Find the numbers.

Advertisement Remove all ads

Solution 1

 Let the three numbers be a d, a and a + d.

S3 = 12

a d + a + a + d = 12

⇒ 3a = 12

a = 4          .....(1)

 (ad)3+a3+(a+d)3=288

(4d)3+43+(4+d)3=288

64+d3+48d+12d2+64+64d348d+12d2=288

24d2=96

d=±2

If d = 2, then the numbers are (4 − 2), 4 and (4 + 2), that is, 2, 4 and 6.

If d = −2, then the numbers are (4 + 2), 4 and (4 − 2), that is, 6, 4 and 2

Solution 2

In the given problem, the sum of three terms of an A.P is 12 and the sum of their cubes is 288.

We need to find the three terms.

Here,

Let the three terms b (a - d), a, (a + d) where a is the first term and d is the common difference of the A.P

So,

(a - d) + a + (a + d) = 12

3a = 12

`a= 12/3`

a = 4

Also, it is given that

`(a - d)^3 + a^3 + (a + d)^3  = 288`

So, using the properties:

`(a - b)^3 = a^3 - b^3 + 3ab^2  - 3a^2b`

`(a + b)^3 = a^3 + b^3 + 3ab^2 + 3a^2b`

We get

`(a - d)^3 + a^3 + (a + d)^3  = 288`

`a^3 - d^3 - 3a^3d^2a + a^3 + a^3 + d^3 + 3a^2d + 3d^2a = 288`

`3a^3 + 6d^2a = 288`

`a^3 + 2d^2 a = 96`

Further solving for by substituting the value of a, we get,

`(4)^3 + 2d^2 (4) = 96`

`64 + 8d^2 = 96`

`8d^2 = 96 - 64``

`d^2 = 32/8`

On further simplification we get

d = 4

`d= sqrt4`

`d = +2`

Now, here d can have two values +2 and -2

So, on substituting the values of a = 4 and d = -2 in three terms we get

First term = a - d

So, 

a - d = 4 - 2

= 2

Second term = a

So,

a = 4

Third term = a + d

So,

a + d = 4  + 2

 = 6

Also on substituting the values of a = 4 and d = -2 in three terms, we get

First term = a - d

So,

a - d  = 4 - (-2)

= 4 + 2

= 6

Second term = a

So,

a = 4

Third term = a + d

So,

a + d = 4 + (-2)

= 4 - 2

 = 2

Therefore the three terms are 2, 4 and 6 or 6, 4 and 2

Concept: Arithmetic Progression
  Is there an error in this question or solution?

APPEARS IN

RD Sharma Class 10 Maths
Chapter 5 Arithmetic Progression
Exercise 5.5 | Q 7 | Page 30
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×