Answer 1

Let the first three terms be a-d, a, a+d
We have been given that the sum of the first three terms of an A.P is 18
Equation becomes

a - d + a + a + d = 18

3a = 18

⇒ a = 6

Also, we have given the product of first and third term is 5 times the common difference

(a - d) (a + d) = 5d

a² - d² = 5d

⇒ a² = 5d + d2 ................(∵ a = 6)

⇒ d² + 5d = 36

⇒ d² + 5d - 36 = 0

d² + 9d - 4d - 36 = 0

⇒ d (d + 9) - 4 (d + 9) =0

⇒ (d - 4) (d + 9) = 0

⇒ d = 4, -9

When d = 4

First three numbers will be 6 -4, 6, 6+4
⇒ 2, 6, 10
When d= - 9
First three numbers will be 6 - (-9), 6, 6+ (-9)
⇒ 15, 6, -3