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MCQ
Fill in the Blanks
The sum of first 16 terms of the AP: 10, 6, 2,... is ______.
Options
–320
320
–352
–400
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Solution
The sum of first 16 terms of the AP: 10, 6, 2,... is –320.
Explanation:
Given, AP is 10, 6, 2,…
Here, first term a = 10
Common difference
d = – 4
∴ `S_16 = 16/2 [2a + (16 - 1)d]` .......`[because S_n = n/2 (2a + (n - 1)d}]`
= `8[2 xx 10 + 15 (-4)]`
= `8(20 - 60)`
= `8(-40)`
= – 320
Concept: Sum of First n Terms of an A.P.
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