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The Sum of 4th and 8th Terms of an A.P. is 24 and the Sum of the 6th and 10th Terms is 34. Find the First Term and the Common Difference of the A.P. - Mathematics

The sum of 4th and 8th terms of an A.P. is 24 and the sum of the 6th and 10th terms is 34. Find the first term and the common difference of the A.P.

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Solution

Let a be the first term and d be the common difference. Then,

\[a_4 + a_8 = 24\]

\[ \Rightarrow a + \left( 4 - 1 \right)d + a + \left( 8 - 1 \right)d = 24\]

\[ \Rightarrow a + 3d + a + 7d = 24\]

\[ \Rightarrow 2a + 10d = 24 \]

\[ \Rightarrow a + 5d = 12 . . . (i)\]

\[\text { Also }, a_6 + a_{10} = 34\]

\[ \Rightarrow a + \left( 6 - 1 \right)d + a + \left( 10 - 1 \right)d = 34\]

\[ \Rightarrow a + 5d + a + 9d = 34\]

\[ \Rightarrow 2a + 14d = 34\]

\[ \Rightarrow a + 7d = 17 . . . (ii)\]

\[\text { Solving (i) and (ii), we get }: \]

\[2d = 5\]

\[ \Rightarrow d = \frac{5}{2}\]

\[\text { Substituing the value in (i), we get }: \]

\[a + 5\left( \frac{5}{2} \right) = 12\]

\[ \Rightarrow a + \frac{25}{2} = 12\]

\[ \Rightarrow a = \frac{- 1}{2}\]

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 19 Arithmetic Progression
Exercise 19.2 | Q 20 | Page 12
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