# The Students of a Vidyalaya Were Asked to Participate in a Competition for Making And Decorating Pen Holders in the Shape of a Cylinder with a Base, Using Cardboard. Each Pen Holder Was to Be - Mathematics

The students of a Vidyalaya were asked to participate in a competition for making and decorating pen holders in the shape of a cylinder with a base, using cardboard. Each pen holder was to be of radius 3 cm and height 10.5 cm. The Vidyalaya was to supply the competitors with cardboard. If there were 35 competitors, how much cardboard was required to be bought for the competition?

#### Solution

Radius of circular end of cylinder pen holder = 3 cm

Height of pen holder = 10.5 cm

Surface area of 1 pen holder ="CSA of penholder+Area of base of SA of 1 penholder"= 2pirh+pir^2

2pirh+pir^2

= 2xx3.14xx3xx10.5+3.14138

= 132xx1.5+198/7cm

=198+198/7cm^2

=1584/7cm^2

Area of car board sheet used by 1 competitor = 1584/7 cm^2

Area of car board sheet used by 35 competitors=1584/735cm^2=7920cm^2

Concept: Surface Area of Cylinder
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.1 | Q 9 | Page 8

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