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The slopes of the lines given by 12x2 + bxy + y2 = 0 differ by 7. Then the value of b is :
(A) 2
(B) ± 2
(C) ± 1
(D) 1
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Solution
(C)
Given equation is `12x^2+bxy-y^2=0`
Comparing with `Ax^2+2Hxy+By^2=0 ," we get"`
A = 12, 2H = b, B = -1
`m_1+m_2=(-2H)/B=-b/-1=b`
`and m_1m_2=A/B=12/-1=-12`
According to given condition,
`|m_1-m_2|=7`
`(m_1-m_2)^2=49`
`b^2-4(-12)=4`
`b^2=49-48`
`b=+-1`
Concept: Acute Angle Between the Lines
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