The slope of a line joining P(6, k) and Q (1-3k, 3) is `1/2` Find
1) k
2) A midpoint of PQ, using the value of ‘k’ found in (1).
Advertisement Remove all ads
Solution
1) Slope of PQ = `(3-k)/(1 - 3k - 6)`
`=> 1/2 = (3-k)/(-3k - 5)`
⇒ -3k - 5 = 2(3 - k)
⇒ -3k - 5 = 6 - 2k
=> k = -11
2) Substituting k in P and Q, we get
P(6, k) = P 6, 11 and Q(1-3k,3) = Q(34,3)
∴ Midpoint of PQ = `((6+34)/2 , (-11+3)/2) = (40/2 , (-8)/2) = (20 , -4)`
Concept: Slope of a Line
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
