Advertisement Remove all ads

# The Sides of a Square Are X = 6, X = 9, Y = 3 and Y = 6. Find the Equation of a Circle Drawn on the Diagonal of the Square as Its Diameter. - Mathematics

The sides of a square are x = 6, x = 9, y = 3 and y = 6. Find the equation of a circle drawn on the diagonal of the square as its diameter.

Advertisement Remove all ads

#### Solution

According to the question:
Sides of the square are x = 6, x = 9, y = 3 and y = 6.
The vertices of the square are (6, 6), (9, 6), (9, 3) and (6, 3).
And, the vertices of two diagonals are (6, 6), (9, 3) and (9, 6), (6, 3).
Hence, the equation of the circle is $\left( x - 6 \right)\left( x - 9 \right) + \left( y - 6 \right)\left( y - 3 \right)$ or

$x^2 + y^2 - 15x - 9y + 72 = 0$
Concept: Circle - Standard Equation of a Circle
Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 24 The circle
Exercise 24.3 | Q 3 | Page 37
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?