# The Sides of a Triangle Are 16 Cm, 12 Cm, and 20 Cm. Find : (I) Area of the Triangle ; (Ii) Height of the Triangle, Corresponding to the Largest Side ; (Iii) Height of the Triangle, Corresponding - Mathematics

Sum

The sides of a triangle are 16 cm, 12 cm, and 20 cm. Find :

(i) area of the triangle ;
(ii) height of the triangle, corresponding to the largest side ;
(iii) height of the triangle, corresponding to the smallest side.

#### Solution

Sides of ∆ are
a = 20 cm
b = 12 cm
c = 16 cm

S = (a + b + c)/2

= (20 + 12 + 16)/2

= 48/2 = 24

area of Δ = sqrt(s(s - a)(s - b)(s - c))

= sqrt(24(24 - 20)(24 - 12)(24 - 16))

= sqrt(24 xx 4 xx 12 xx 8)

= sqrt(12 xx 2 xx 4 xx 12 xx 2 xx 4)

= sqrt(12 xx 12 xx 4 xx 4 xx 2 xx 2)

= 12 xx 4 xx 2 = 96  "cm"^2

AD is height of Δ corresponding to largest side.

∴ 1/2 xx "BC" xx "AD" = 96

1/2 xx 20 xx "AD" = 96

AD = (96 xx 2)/20

BE is height of Δ corresponding to smallest side.

∴ 1/2 "AC" xx "BE" = 96

1/2 xx 12 xx "BE" = 96

BE = (96 xx 2)/12

BE = 16 cm

(i) 96 cm2 (ii) 9.6 cm (iii) 16 cm

Is there an error in this question or solution?
Chapter 20: Area of a Trapezium and a Polygon - Exercise 20 (A) [Page 223]

#### APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 20 Area of a Trapezium and a Polygon
Exercise 20 (A) | Q 3 | Page 223
Share