Department of Pre-University Education, Karnataka course PUC Karnataka Science Class 12
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# The Short-wavelength Limit Shifts by 26 Pm When the Operating Voltage in an X-ray Tube is Increased to 1.5 Times the Original Value. What Was the Original Value of the Operating Voltage? - Physics

ConceptElectromagnetic Spectrum

#### Question

The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage?

(Use Planck constant h = 6.63 × 10-34 Js= 4.14 × 10-15 eVs, speed of light c = 3 × 108 m/s.)

#### Solution

Let lambda be the initial wavelength, V be the initial potential, lambda^'be the new wavelength and V' be the new operating voltage when the operating voltage is increased in the X-ray tube.

Given :-

lambda^' = lambda - 26  "pm"

V = 1.5 V

Energy (E) is given by

E = (hc)/lambda

⇒ eV = (hc)/lambda

Here,
h = Planck's constant
c = Speed of light
lambda = Wavelength of light
V = Operating potential

therefore lambda = (hc)/(eV)

⇒ lambdaV = lambda^'V^' ............[∵ lambda ∝ 1/V]

⇒ lambda V = (lambda - 26) xx 1.5 V

⇒ 0.5lambda = 26 xx 1.5

⇒ lambda = 26 xx 3

⇒ lambda = 78  "pm"

Hence, the initial wavelength is 78 xx 10^-12  "m".

Now, the operating voltage (V) is given by

V = (hc)/(elambda)

⇒ V = (6.63 xx 10^-34 xx 3 xx 10^8)/(1.6 xx 10^-19 xx 78 xx 10^-12)

⇒ V = 0.15937 xx 10^5

⇒ V = 15.9  "kV"

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Solution The Short-wavelength Limit Shifts by 26 Pm When the Operating Voltage in an X-ray Tube is Increased to 1.5 Times the Original Value. What Was the Original Value of the Operating Voltage? Concept: Electromagnetic Spectrum.
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