Sum
The shadow of a building is 20 m long when the angle of elevation of the sun is 60º. Find the height of the building
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Solution
Let AB be the building and AC be its shadow.
Then, AC = 20 m and ∠ACB = 60º.
Let AB = h.
Then,
`\frac { AB }{ AC } = tan 60º = √3`
⇒ h/20 = √3
∴ h = (20 × √3 )m = (20 × 1.732) m
= 34.64 m.
Concept: Heights and Distances
Is there an error in this question or solution?
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