Answer 1

\[\text{ Height of the liquid in the capillary tube is given by }: \]

\[\text{ h } = \frac{2Scos\theta}{r\rho g}\]

\[\text{ h = Height }\]

\[\text{ S = Surface tension }\]

\[\text{ r = Inner radius of the tube }\]

\[\rho = \text{ Density of the liquid }\]

\[\text{ g = Acceleration due to gravity }\]

\[a) \theta \text{ and } \rho \text{ depend upon the material of the capillary tube and the liquid }. \]

\[b) \text{ h is dependent on the length of the tube . If the length is insufficient, then h will be low } . \]

\[d) \text{ r is the inner radius of the tube } .\]