The ratio of prices of two houses was 2 : 3. Two years later when price of first house has increased by 30% and that of the second by ₹ 90,000 the ratio of prices becomes 5 : 7. Find the original prices of two houses.
Solution
Ratio of the prices of two houses 2 : 3
Let price of house I be 2x and price of house 2 be 3x.
After two years, price of house· 1 is increased by 30%
∴ New price of house 1 is
`"2x" + 30/100 xx "2x"`
2x + 0.6 x = 2.6 x
Price of house 2 is increased by 90,000
∴ New price of house 2 is
3x + 90000
The ratio of the new prices of two houses is 5: 7
`(2.6"x")/(3"x" + 90000) = 5/7`
`therefore 18.2 "x" = 15"x" + 450000`
3.2 x = 450000
x = `450000/3.2`
= 140625
Original price of house 1 is
2 x = 2 x 1,40,625 = ₹ 2,81,250
Original price of house 2 is
3 x = 3 x 1,40,625 = ₹ 4,2l,875
