# The Ratio of Prices of Two Houses Was 2 : 3. - Mathematics and Statistics

Sum

The ratio of prices of two houses was 2 : 3. Two years later when price of first house has increased by 30% and that of the second by ₹  90,000 the ratio of prices becomes 5 : 7. Find the original prices of two houses.

#### Solution

Ratio of the prices of two houses 2 : 3

Let price of house I be 2x and price of house 2 be 3x.

After two years, price of house· 1 is increased by 30%

∴ New price of house 1 is

"2x" + 30/100 xx "2x"

2x + 0.6 x = 2.6 x

Price of house 2 is increased by 90,000

∴ New price of house 2 is

3x + 90000

The ratio of the new prices of two houses is 5: 7

(2.6"x")/(3"x" + 90000) = 5/7

therefore 18.2 "x" = 15"x" + 450000

3.2 x = 450000

x = 450000/3.2

= 140625

Original price of house 1 is

2 x = 2 x 1,40,625 = ₹ 2,81,250

Original price of house 2 is

3 x = 3 x 1,40,625 = ₹ 4,2l,875

Concept: Ratio, Proportion and Partnership
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