Share

# The Ratio of the Intensities at Minima to the Maxima in the Young'S Double Slit Experiment is 9 : 25. Find the Ratio of the Widths of the Two Slits. - Physics

#### Question

The ratio of the intensities at minima to the maxima in the Young's double slit experiment is 9 : 25. Find the ratio of the widths of the two slits.

#### Solution

Let w, a,I represent the slit width, amplitude and intensity.

I_(min)/I_(max)=(a_1-a_2)^2/(a_1+a_2)^2=9/25

((a_1-a_2))/((a_1+a_2))=3/5

Or

a_1/a_2=4/1

and

w_1/w_2=(a_2)^2/(a_2)^2=16/1

Is there an error in this question or solution?