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The Ratio of the Intensities at Minima to the Maxima in the Young'S Double Slit Experiment is 9 : 25. Find the Ratio of the Widths of the Two Slits. - Physics

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Question

The ratio of the intensities at minima to the maxima in the Young's double slit experiment is 9 : 25. Find the ratio of the widths of the two slits.

Solution

Let w, a,I represent the slit width, amplitude and intensity.

`I_(min)/I_(max)=(a_1-a_2)^2/(a_1+a_2)^2=9/25`

`((a_1-a_2))/((a_1+a_2))=3/5`

Or 

`a_1/a_2=4/1`

and 

`w_1/w_2=(a_2)^2/(a_2)^2=16/1`

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The Ratio of the Intensities at Minima to the Maxima in the Young'S Double Slit Experiment is 9 : 25. Find the Ratio of the Widths of the Two Slits. Concept: Interference of Light Waves and Young’S Experiment.
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