# The probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 2 will miss the target. - Mathematics and Statistics

Sum

The probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 2 will miss the target.

#### Solution

Let X = number of bombs hitting the target.

p = probability that bomb will hit the target

∴ p = 0.8 = 8/10 = 4/5

∴ q = 1 - p = 1 - 4/5 = 1/5

Given: n = 10

∴ X ~ B (10, 4/5)

The p.m.f. of X is given as :

P[X = x] = "^nC_x  p^x  q^(n - x)

i.e. p(x) = "^10C_x (4/5)^x (1/5)^(10 - x)

P (exactly 2 bombs will miss the target)

= P (exactly 8 bombs will hit the target)

= P[X = 8] = p(8)

= "^10C_8 (4/5)^8 (1/5)^(10 - 8)

= "^10C_2 (4/5)^8 (1/5)^2   ....[because "^nC_x = "^nC_(n - x)]

= (10 xx 9)/(1 xx 2) xx 4^8/5^10 = (45 xx 4^8)/5^10 = 45(2^16/5^10)

Hence, the probability that exactly 2 bombs will miss the target = 45(2^16/5^10)

#### Notes

[Note: Answer in the textbook is incorrect.]

Concept: Binomial Distribution
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#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 12th Standard HSC Maharashtra State Board
Chapter 8 Binomial Distribution
Miscellaneous exercise 8 | Q 4 | Page 254