Maharashtra State BoardHSC Arts 12th Board Exam
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The Probability Mass Function (P.M.F.) of X is Given Below - Mathematics and Statistics

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The probability mass function (p.m.f.) of X is given below:

X=x 1 2 3
P (X= x) 1/5 2/5 2/5

 find E(X2)

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Solution

x P(x) xP(x) x2P(x)
1 1/5 1/5 1/5
2 2/5 4/5 8/5
3 2/5 6/5 18/5
     

`sumx^2P(x)=27/5`

`E(x^2)=sum x^2P(x)=27/5`

 

Concept: Probability Distribution - Probability Mass Function (P.M.F.)
  Is there an error in this question or solution?

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