#### Question

The principal solution of `cos^-1(-1/2)` is :

(a) π/3

(b) π/6

(c) 2π/3

(d) 3π/2

#### Solution

The principal solution of `cos^-1(-1/2)= ` An angle in [0,π], whose cosine is -1/2

⇒ `cos^-1(-1/2)=(2pi)/3`

Is there an error in this question or solution?

#### APPEARS IN

Solution The principal solution of cos-1(-1/2) is Concept: Inverse Trigonometric Functions - Inverse Trigonometric Functions - Principal Value Branch.