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The Present Population of a Town is 25000. It Grows at 4%, 5% and 8% During First Year, Second Year and Third Year Respectively. Find Its Population After 3 Years. - Mathematics

Sum

The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.

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Solution

Here,
P = Initial population = 25, 000
\[ R_1 = 4 % \]
\[ R_2 = 5 % \]
\[ R_3 = 8 % \]
n = Number of years = 3
∴ Population after three years = P \[\left( 1 + \frac{R_1}{100} \right)\left( 1 + \frac{R_2}{100} \right)\left( 1 + \frac{R_3}{100} \right)\]
\[ = 25, 000\left( 1 + \frac{4}{100} \right)\left( 1 + \frac{5}{100} \right)\left( 1 + \frac{8}{100} \right)\]
\[ = 25, 000\left( 1 . 04 \right)\left( 1 . 05 \right)\left( 1 . 08 \right)\]
 = 29, 484
Hence, the population after three years will be 29, 484.

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 14 Compound Interest
Exercise 14.4 | Q 3 | Page 27
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