# The Present Age of a Man is Twice that of His Son. Eight Years Hence, Their Ages Will Be in the Ratio 7 : 4. Find Their Present Ages - Mathematics

Sum

The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages

#### Solution

Let present age of son = x year

Then age of his father = 2x

8 years hence,

Age of son = (x + 8) years and age of father = (2x + 8) years

According to the condition,

(2"x" + 8)/("x" + 8) = 7/4

⇒ 8x + 32 = 7x + 56

⇒ 8x – 7x = 56 – 32

⇒ x = 24

Present age of son = 24 years

and age of father = 2x = 2 x 24 = 48 years

Hence age of man = 48 years and age of his son = 24 years

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#### APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 14 Linear Equations in one Variable
Exercise 14 (B) | Q 20 | Page 169