Advertisement Remove all ads

# The Population of a Town Increases at the Rate of 40 per Thousand Annually. If the Present Population Be 175760, What Was the Population Three Years Ago. - Mathematics

Sum

The population of a town increases at the rate of 40 per thousand annually. If the present population be 175760, what was the population three years ago.

Advertisement Remove all ads

#### Solution

Population after three years = P $\left( 1 + \frac{R}{100} \right)^3$
$175, 760 = P \left( 1 + \frac{40}{1000} \right)^3$
$175, 760 = P \left( 1 . 04 \right)^3$
$P = \frac{175, 760}{1 . 124864}$
$= 156, 250$
Thus, the population three years ago was 156, 250.

Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 14 Compound Interest
Exercise 14.4 | Q 13 | Page 28
Advertisement Remove all ads

#### Video TutorialsVIEW ALL 

Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?
Course