#### Question

The plate resistance of a triode is 8 kΩ and the transconductance is 2.5 millimho. (a) If the plate voltage is increased by 48 V and the grid voltage is kept constant, what will be the increase in the plate current? (b) With plate voltage kept constant at this increased value, by how much should the grid voltage be decreased in order to bring the plate current back to its initial value?

#### Solution

Given:-

Plate resistance,

`r_p=8KOmega=8000kOmega`

Change in plate voltage,

`deltaV_p=48V`

Formula for plate resistance:

\[r_P = \left( \frac{\delta V_P}{\delta I_P} \right)_{V_G = \text{constant}} \]

\[ \Rightarrow \delta I_p = \frac{\delta V_p}{r_p} {}_{V_{G = \text{constant}}} \]

\[ \Rightarrow \delta I_p = \frac{48}{8000} = 0 . 006 A = 6 \text{ mA}\]

(b) Now, V_{p} is kept constant.

Change in plate current,

`deltaI_p=6"mA"=0.006A`

Trasconductance,

\[g_m = 0 . 0025 mho\]

\[\delta V_G = \frac{\delta I_p}{g_m} = \frac{0 . 006}{0 . 0025}\]

\[\delta V_G = 2 . 4 V, \text{ at constant plate voltage}\]