#### Question

A triode value operates at V_{p} = 225 V and V_{g} = −0.5 V.

The plate current remains unchanged if the plate voltage is increased to 250 V and the grid voltage is decreased to −2.5 V. Calculate the amplification factor.

#### Solution

Amplification factor for a triode valve,

\[\mu = \frac{\text{Change in Plate Voltage}}{\text{Change in Grid Voltage}}\]

At constant plate current,

\[\mu = \left(\frac{\delta V_P}{\delta V_G}\right)_{i_P = constant} \]

\[\mu = \frac{250 - 225}{2 . 5 - 0 . 5}\]

\[\mu = \frac{25}{2} = 12 . 5\]

This implies that the amplification factor of the triode is 12.5

Is there an error in this question or solution?

Solution The Plate Current Remains Unchanged If the Plate Voltage is Increased to 250 V and the Grid Voltage is Decreased to −2.5 V. Calculate the Amplification Factor. Concept: Semiconductor Diode.