Sum

A triode value operates at V_{p} = 225 V and V_{g} = −0.5 V.

The plate current remains unchanged if the plate voltage is increased to 250 V and the grid voltage is decreased to −2.5 V. Calculate the amplification factor.

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#### Solution

Amplification factor for a triode valve,

\[\mu = \frac{\text{Change in Plate Voltage}}{\text{Change in Grid Voltage}}\]

At constant plate current,

\[\mu = \left(\frac{\delta V_P}{\delta V_G}\right)_{i_P = constant} \]

\[\mu = \frac{250 - 225}{2 . 5 - 0 . 5}\]

\[\mu = \frac{25}{2} = 12 . 5\]

This implies that the amplification factor of the triode is 12.5

Concept: Semiconductor Diode

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