# The Piston in the Cylinder Head of a Locomotive Has a Stroke (Twice the Amplitude) of 1.0 M. If the Piston Moves with Simple Harmonic Motion with an Angular Frequency of 200 Rad/Min, What is Its Maximum Speed? - Physics

The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is its maximum speed?

#### Solution 1

Stroke of piston = 2 times the amplitude

Let A = amplitude,stroke =  1 m

:. => A =  1/2 m

Angular frequency,  omega = 200 "rad/min"

V_"max" = ?

We know that the maximum speed of the block when the amplitude is A

V_"max" = omegaA = 200 xx 1/2 = 100 "m.min"

= 100/60 = 5/3 ms6(-1)= 1.67 ms^(-1)

#### Solution 2

Angular frequency of the piston, ω = 200 rad/ min.

Stroke = 1.0 m

Amplitude, A = 1.0/ 2= 0.5 m

The maximum speed (vmax) of the piston is give by the relation:

V_"max" = Aomega

= 200 xx 0.5 = 100 "m/min"

Concept: Periodic and Oscillatory Motions
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#### APPEARS IN

NCERT Class 11 Physics
Chapter 14 Oscillations
Q 14 | Page 360