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The Ph of a Sample of Vinegar is 3.76. Calculate the Concentration of Hydrogen Ion in It. - CBSE (Science) Class 11 - Chemistry

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Question

The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

Solution 1

Given

pH = 3.76

it is known that

pH =  -log[`H^(+)`]

`=> log[H^+] = -pH` 

`=> [H^(+)] = "antilog" (-pH)`

`= "antilog"(-3.76)`

`= 1.74 xx 10^(-4) M`

Hence, the concentration of hydrogen ion in the given sample of vinegar is 1.74 × 10–4M.

Solution 2

pH = – log [H+] or log [H+] = – pH = – 3.76 = 4.24
∴ [H+] = Antilog 4.24 = 1.738 x  10-4 = 1.74 x 10-4 M

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Solution The Ph of a Sample of Vinegar is 3.76. Calculate the Concentration of Hydrogen Ion in It. Concept: Ionization of Acids and Bases - The pH Scale.
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