Answer 1

Let O be the centre of the circle with radius 5.6 cm and OACB be its sector with perimeter 27.2 cm.

Thus, we have:

OA + OB + arc AB = 27.2

⇒ 5.6 + 5.6 + arc AB = 27.2

⇒  arc AB = 16 cm

Now,

Area of the sector OACBO` = (1/2xx"Radius"xxl)"square Units"`

`=(1/(2)5.6xx16)"cm"^20`

= 44.8 cm²