The Perimeter of a Triangle is 8y2 – 9y + 4 and Its Two Sides Are 3y2 – 5y and 4y2 + 12. Find Its Third Side. - Mathematics

Sum

The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.

Solution

Perimeter of the triangle = Sum of three sides

= 8y2 – 9y + 4

Sum of two sides = 3y2 – 5y  + 4y2 + 12

= 7y2 − 5y + 12

∴ (8y2  – 9y + 4)  – (7y2  – 5y + 12)

= 8y2  – 9y + 4  – 7y2 + 5y  – 12

= y2  – 4y  – 8

Hence third side = y2  – 4y  – 8

Concept: Combining like Terms
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 11 Algebraic Expressions
Exercise 11 (B) | Q 11 | Page 140