# The odds against a husband who is 55 years old living till he is 75 is 8: 5 and it is 4: 3 against his wife who is now 48, living till she is 68. Find the probability that the couple will be alive 20 - Mathematics and Statistics

Sum

The odds against a husband who is 55 years old living till he is 75 is 8: 5 and it is 4: 3 against his wife who is now 48, living till she is 68. Find the probability that the couple will be alive 20 years hence.

#### Solution

Let A be the event that husband would be alive after 20 years.
Odds against A are 8: 5
∴ The probability of occurrence of event A is given by

P(A) = 5/(8 + 5) = 5/13

∴ P(A') = 1 – P(A) = 1 - 5/13 = 8/13
Let B be the event that wife would be alive after 20 years.
Odds against B are 4: 3
∴ The probability of occurrence of event B is given by

P(B) = 3/(4 + 3) = 3/7

∴ P(B') = 1 – P(B) = 1 - 3/7 = 4/7
Since A and B are independent events
∴ A' and B' are also independent events
Let X be the event that both will be alive after 20 years.
∴ P(X) = (A ∩ B)

∴ P(X) = P(A).P(B) = 5/13 xx 3/7 = 15/91

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Chapter 7: Probability - Miscellaneous Exercise 7 [Page 110]

#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 11th Standard HSC Maharashtra State Board
Chapter 7 Probability
Miscellaneous Exercise 7 | Q 9. (a) | Page 110
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